4x^2-80x+150=0

Solution for 4x^2-80x+150=0 equation:

4x^2-80x+150=0

a = 4; b = -80; c = +150;
Δ = b2-4ac
Δ = -802-4·4·150
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-20\sqrt{10}}{2*4}=\frac{80-20\sqrt{10}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+20\sqrt{10}}{2*4}=\frac{80+20\sqrt{10}}{8}
$